x^2+1x-2187=0

Solution for x^2+1x-2187=0 equation:

x^2+1x-2187=0

We add all the numbers together, and all the variables

x^2+x-2187=0

a = 1; b = 1; c = -2187;
Δ = b2-4ac
Δ = 12-4·1·(-2187)
Δ = 8749
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{8749}}{2*1}=\frac{-1-\sqrt{8749}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{8749}}{2*1}=\frac{-1+\sqrt{8749}}{2}
$